自然资源部晒出我国矿产资源“家底” 矿业绿色发展取得
人民网北京12月3日电 (记者杨曦)矿产资源家底数据是基本国情国力的重要组成部分。近日,自然资源部发布的《中
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-> SELECT c.first_name, c.last_name, a.address -> FROM customer c JOIN address a;
SELECT "2020-01-01" dtUNION ALLSELECT "2020-01-02" dtUNION ALLSELECT "2020-01-03" dtUNION ALL.........SELECT "2020-12-29" dtUNION ALLSELECT "2020-12-30" dtUNION ALLSELECT "2020-12-31" dt
-> SELECT ones.num + tens.num + hundreds.num -> FROM -> (SELECT 0 num UNION ALL -> SELECT 1 num UNION ALL -> SELECT 2 num UNION ALL -> SELECT 3 num UNION ALL -> SELECT 4 num UNION ALL -> SELECT 5 num UNION ALL -> SELECT 6 num UNION ALL -> SELECT 7 num UNION ALL -> SELECT 8 num UNION ALL -> SELECT 9 num) ones -> CROSS JOIN -> (SELECT 0 num UNION ALL -> SELECT 10 num UNION ALL -> SELECT 20 num UNION ALL -> SELECT 30 num UNION ALL -> SELECT 40 num UNION ALL -> SELECT 50 num UNION ALL -> SELECT 60 num UNION ALL -> SELECT 70 num UNION ALL -> SELECT 80 num UNION ALL -> SELECT 90 num) tens -> CROSS JOIN -> (SELECT 0 num UNION ALL -> SELECT 100 num UNION ALL -> SELECT 200 num UNION ALL -> SELECT 300 num) hundreds;
-> SELECT DATE_ADD("2020-01-01", -> INTERVAL (ones.num + tens.num + hundreds.num) DAY) dt -> FROM -> (SELECT 0 num UNION ALL -> SELECT 1 num UNION ALL -> SELECT 2 num UNION ALL -> SELECT 3 num UNION ALL -> SELECT 4 num UNION ALL -> SELECT 5 num UNION ALL -> SELECT 6 num UNION ALL -> SELECT 7 num UNION ALL -> SELECT 8 num UNION ALL -> SELECT 9 num) ones -> CROSS JOIN -> (SELECT 0 num UNION ALL -> SELECT 10 num UNION ALL -> SELECT 20 num UNION ALL -> SELECT 30 num UNION ALL -> SELECT 40 num UNION ALL -> SELECT 50 num UNION ALL -> SELECT 60 num UNION ALL -> SELECT 70 num UNION ALL -> SELECT 80 num UNION ALL -> SELECT 90 num) tens -> CROSS JOIN -> (SELECT 0 num UNION ALL -> SELECT 100 num UNION ALL -> SELECT 200 num UNION ALL -> SELECT 300 num) hundreds -> WHERE DATE_ADD("2020-01-01", -> INTERVAL (ones.num + tens.num + hundreds.num) DAY) < "2021-01-01" -> ORDER BY 1;
-> SELECT c.first_name, c.last_name, a.address -> FROM customer c JOIN address a -> ON c.address_id = a.address_id;
SELECT c.first_name, c.last_name, a.addressFROM customer c INNER JOIN address a ON c.address_id = a.address_id;
SELECT c.first_name, c.last_name, a.addressFROM customer c INNER JOIN address a USING (address_id);
-> SELECT f.film_id, f.title, count(i.inventory_id) num_copies -> FROM film f -> LEFT OUTER JOIN inventory i -> ON f.film_id = i.film_id -> GROUP BY f.film_id, f.title;
-> SELECT c.first_name, c.last_name, date(r.rental_date) -> FROM customer c -> NATURAL JOIN rental r;Empty set (0.04 sec)
-> SELECT c.first_name, c.last_name, a.address -> FROM customer c, address a -> WHERE c.address_id = a.address_id;
SELECT STRAIGHT_JOIN c.first_name, c.last_name, ct.cityFROM city ct INNER JOIN address a ON a.city_id = ct.city_id INNER JOIN customer c ON c.address_id = a.address_id
-> SELECT f.film_id, f.title, i.inventory_id, r.rental_date -> FROM film f -> LEFT OUTER JOIN inventory i -> ON f.film_id = i.film_id -> LEFT OUTER JOIN rental r -> ON i.inventory_id = r.inventory_id -> WHERE f.film_id BETWEEN 13 AND 15;
-> SELECT f.title, f_prnt.title prequel -> FROM film f -> INNER JOIN film f_prnt -> ON f_prnt.film_id = f.prequel_film_id -> WHERE f.prequel_film_id IS NOT NULL;
-> SELECT 1 num, "abc" str -> UNION -> SELECT 9 num, "xyz" str;
-> SELECT a.first_name fname, a.last_name lname -> FROM actor a -> WHERE a.first_name LIKE "J%" AND a.last_name LIKE "D%" -> UNION ALL -> SELECT c.first_name, c.last_name -> FROM customer c -> WHERE c.first_name LIKE "J%" AND c.last_name LIKE "D%" -> ORDER BY lname, fname;
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